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How to display only 5 records per page from my mysql database table through pagination?

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北恋
北恋 2021-01-06 11:51

I want to display five record per page through pagination (mysql,php,html,css) until all the records are displayed, navigation to pages must be like,

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6条回答
  • 一整个雨季
    2021-01-06 12:30

    Link is here for demo, click here to experience the result

    Here is the code working for me, just change your db name, username and password and get pagination done. You can change $rec_limit value to your desired no. of records per page.

    <?php 
  $host="localhost";
  $username="68"; 
  $password="67242"; 
  $database="68";

   $rec_limit = 5;
    $conn = mysql_connect($localhost,$username,$password);

    if(! $conn ) {
    die('Could not connect: ' . mysql_error());
 }
 mysql_select_db('10');

 /* Get total number of records */
 $sql = "SELECT count(emp_id) FROM emp_master ";
 $retval = mysql_query( $sql, $conn );

 if(! $retval ) {
    die('Could not get data: ' . mysql_error());
 }
 $row = mysql_fetch_array($retval, MYSQL_NUM );
 $rec_count = $row[0];

 if( isset($_GET{'page'} ) ) {
    $page = $_GET{'page'} + 1;
    $offset = $rec_limit * $page ;
 }else {
    $page = 0;
    $offset = 0;
 }

 $left_rec = $rec_count - ($page * $rec_limit);
 $sql = "SELECT eid,ename, email, quali, gender, contactno, birthdate, joiningdate,CURDATE(), TIMESTAMPDIFF( YEAR, birthdate, CURDATE( ) ) AS age ". 
    "FROM emp_master ".
    "LIMIT $offset, $rec_limit";

 $retval = mysql_query( $sql, $conn );

 if(! $retval ) {
    die('Could not get data: ' . mysql_error());
 }


  echo "<table border='1'>";
  $i = 0;
  while($row = mysql_fetch_array($retval, MYSQL_ASSOC)) {

   if ($i == 0) {
        $i++;
        echo "<tr>";
        foreach ($row as $key => $value) {
          echo "<th>" . $key . "</th>";
        }
        echo "</tr>";
        }
        echo "<tr>";
        foreach ($row as $value) {
        echo "<td>" . $value . "</td>";
       }
      echo "</tr>";

     }
    echo "</table>";

if( $page > 0 ) {
$last = $page - 2;
echo "<a href = \"$_PHP_SELF?page=$last\">Last 5 Records</a> | ";
echo "<a href = \"$_PHP_SELF?page=$page\">Next 5 Records</a>";

}else if( $page == 0 ) {
$page = $page + 0;
echo "<a href = \"$_PHP_SELF?page=$page\">Next 5 Records</a>";

}else if( $left_rec < $rec_limit ) {

$last = $page - 2;
echo "<a href = \"$_PHP_SELF?page=$last\">Last 5 Records</a>";

}

     mysql_close($conn);
php?>
    0 讨论(0)
  • 故里飘歌
    2021-01-06 12:33

    You can use a library called dataTables that will auto paginate the data and you can easily customize it to suit your needs with the look and how many records to show per page. It also has a search field which enables users to search your data without any extra code.

    All you have to do is include a couple of cdn's and the following code and everything works fine

    $(document).ready(function(){
    $('#myTable').DataTable();
});

    Some examples here

    0 讨论(0)
  • 被撕碎了的回忆
    2021-01-06 12:36

    you just should remove spaces in href and also make $page = $page + 1 when page is 0

    if( $page > 0 ) {
    $last = $page - 2;
    echo "<a href = \"$_PHP_SELF?page=$last\">Last 10 Records</a> |";
    echo "<a href = \"$_PHP_SELF?page=$page\">Next 10 Records</a>";
 }else if( $page == 0 ) {
    $page = $page + 1;
    echo "<a href = \"$_PHP_SELF?page=$page\">Next 10 Records</a>";
 }else if( $left_rec < $rec_limit ) {
    $last = $page - 2;
    echo "<a href = \"$_PHP_SELF?page=$last\">Last 10 Records</a>";
 }
    0 讨论(0)
  • 执念已碎
    2021-01-06 12:38

    IF your are using mysqli the code is below

     $conn=mysqli_connect("localhost","root","","ui");


 $start=0;
  $limit=5;

  $t=mysqli_query($conn,"select * from form_table");
  $total=mysqli_num_rows($t);



   if(isset($_GET['id']))
   {
        $id=$_GET['id'] ; 
                        $start=($id-1)*$limit;

                          }
            else
            {
        $id=1;
   }
   $page=ceil($total/$limit);

   $query=mysqli_query($conn,"select * from form_table limit                                        $start, $limit");
 ?>
 <!DOCTYPE html>
 <html>
 <head>
 <meta name="viewport" content="width=device-width, initial-scale=1">
 <link rel="stylesheet"           href="http://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/css/bootstrap.min.css">
 <script s             src="https://ajax.googleapis.com/ajax/libs/jquery/1.12.4/jquery.min.js">           </script>
     <script                           src="http://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/js/bootstrap.min.js">                 </script>
     </head>         
 <body>

<div class="container">
 <h2>Table</h2>
    <table class="table table-bordered">
    <thead>
      <tr>
       <th>Id</th>
         <th>Name</th>
       <th>Gender</th>


<th>Hobbies</th>
<th>Course</th>
 </tr>
</thead>
<tbody>

<?php
  while($ft=mysqli_fetch_array($query))
 {?>
 <tr>
<td><?= $ft['0']?></td>
<td><?= $ft['1']?></td>
<td><?= $ft['2']?></td>
<td><?= $ft['3']?></td>
<td><?= $ft['4']?></td>
  </tr>   
<?php
 }

?>


 </tbody>
  </table>
 <ul class="pagination">
  <?php if($id > 1) {?> <li><a href="?id=<?php echo ($id-1) ?       >">Previous</a></li><?php }?>
  <?php
  for($i=1;$i <= $page;$i++){
   ?>
  <li><a href="?id=<?php echo $i ?>"><?php echo $i;?></a></li>
   <?php
   }
  ?>
   <?php if($id!=$page)

   {?>
    0 讨论(0)
  • 故里飘歌
    2021-01-06 12:41

    If you want just PHP MySQL code, I usually use something like the following.

    $page=max(intval($_GET['page']),1); // assuming there is a parameter 'page'
$itemsperpage = 5;
$total=100; // total results if you know it already otherwise use another query
$totalpages = max(ceil($total/$itemsperpage),1);
$query = "SELECT * FROM emp_master LIMIT ".(($page-1)*$itemsperpage).",".$itemsperpage; // this will return 5 items based on the page
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  • 攒了一身酷
    2021-01-06 12:47 
    i Give you an example of my project of pagination. Just you have to put your values in the code

$sql="SELECT * FROM tblname  LIMIT  $next,5";
$results = mysqli_query($conn,$sql);
    }
        else if (isset($_POST['prev']))
        {
            $prev1=$_POST['prev'];
            $next=$_POST['prev'];
            $prev=$prev1;
            $sql="SELECT * FROM tablename  LIMIT  $prev,5";
            $prev=$prev1;
            $results = mysqli_query($conn,"SELECT * FROM tablename LIMIT  $prev,10");   
                if($prev==0)
                {
                    $prev = 0;
                }
                else
                {
                    $prev=$next-10;   
                }
        }
        else
        {
            $next=0;
            $prev=0;
            $results = mysqli_query($conn,"SELECT * FROM tablename LIMIT  $next,10");
        }
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