[removed] find the prototype object to which a property belongs

Question

I have an instance from Square which inherits from Rectangle

instance instanceof Rectangle --> true
instance instanceof Square    --> true
instance.are         


        

Answer 1

No. There isn't. You have to traverse the prototype chain:

function owner(obj, prop) {
    var hasOwnProperty = Object.prototype.hasOwnProperty;
    while (obj && !hasOwnProperty.call(obj, prop))
        obj = Object.getPrototypeOf(obj);
    return obj;
}

Now you simply do:

var obj = owner(instance, "area");
console.log(obj === Rectangle);    // true

If instance or its prototypes do not have the property area then owner returns null.

Answer 2

Replying to you comment: What you essentially seem to want is to call a function of the base class inside the overriding function of an inherited class.

I wouldn't bother with the prototype chain in your case, you can just build base into your inheritance model:

function Rectangle() {}
Rectangle.prototype.area = function () {
    console.log("rectangle");
};

//setting up inheritance
function Square() {}
Square.prototype = Object.create(Rectangle.prototype);
Square.prototype.base = Rectangle.prototype;

Square.prototype.area = function () {
    this.base.area();
    console.log("square");
};

var square = new Square();
square.area();

FIDDLE