Jquery how to check if a input has a number higher then 99

Question

Was wanting to know how to check using jquery if a input contains a number higher then 99

Answer 1

Simply use this:

if ($("input.INPUTNAME").val() > 99) {
//above 99 code
}

You may want to have an else command, if the input is below 99.

if ($("input.INPUTNAME").val() > 99) {
    //above 99 code.
    }
else{
     //Not above 99 code.
}

Answer 2

if(parseInt($(YOURINPUT).val()) > 99) // do something

Answer 3

This would do it

var value = $("input selector").eq(0).val();
if(isNaN(value)){
 //do stuff
}

else{
var num = value - 0;
if(num>99)
{
 //value is greater than 99
}

}

Answer 4

I guess typically with jQuery you would have to have the name of the form

<form id="myForm" action="comment.php" method="post"> 
    number: <input id="form_number" type="text" name="number" /> 
    Comment: <textarea name="comment"></textarea> 
    <input type="submit" value="Submit Comment" /> 
</form>

you would select the form and its input.

var myInt = parseInt(jQuery("#form-number-url").attr("value"));

then you can compare it with any other integer.

Answer 5

Use this:

html:

<input type="text" id="myInput" />

jquery:

var nMyInput = $("#myInput").val();
if (typeof nMyInput != "undefined"){
    if(!isNaN(nMyInput)){
        if (parseInt(nMyInput) > 99) {
            /* do your stuff */
        }
    }
}

Answer 6

If by input you mean text, then use the following:

if (parseFloat($("#inputid").val()) > 99) {
   //do something
}