custom sorting a java array

Question

I have an [] that has some numbers (distances from some point).
I want to create an array of indexes into the first array where the indexes are sorted by the distance.

Answer 1

Works well if you want the indicies as a primative int array then you will have to create your own binary sorter which shouldn't be to difficult.

Edit: I adapted java's mergesorter to work with int's. This should save you a little time in writing your own.

public static void main(String[] args) {
        double[] dist = new double[] {3.2, 1.4, 7.3, 2.2, 9.1};
        int[] indices = createIndicies(dist);

        System.out.println(Arrays.toString(dist) + " " +  Arrays.toString(indices));
    }

    public static int[] createIndicies(double[] array) {
        int[] intArray = new int[array.length];
        for (int j = 0; j < array.length; j++) {
            intArray[j] = j;
        }

        int[] indicies = intArray.clone();
        mergeSort(intArray, indicies, 0, intArray.length, 0, new IndiciesSorter(array));

        return indicies;
    }

    public static class IndiciesSorter implements Comparator<Integer> {

        double[] array;

        public IndiciesSorter(double[] array) {
            this.array = array;
        }

        @Override
        public int compare(Integer o1, Integer o2) {
            return Double.compare(array[o1], array[o2]);
        }
    }

    private static void mergeSort(int[] src, int[] dest, int low,
            int high, int off, Comparator c) {
        int length = high - low;

        // Insertion sort on smallest arrays
        if (length < 7) {
            for (int i = low; i < high; i++)
                for (int j = i; j > low && c.compare(dest[j - 1], dest[j]) > 0; j--)
                    swap(dest, j, j - 1);
            return;
        }

        // Recursively sort halves of dest into src
        int destLow = low;
        int destHigh = high;
        low += off;
        high += off;
        int mid = (low + high) >>> 1;
        mergeSort(dest, src, low, mid, -off, c);
        mergeSort(dest, src, mid, high, -off, c);

        // If list is already sorted, just copy from src to dest. This is an
        // optimization that results in faster sorts for nearly ordered lists.
        if (c.compare(src[mid - 1], src[mid]) <= 0) {
            System.arraycopy(src, low, dest, destLow, length);
            return;
        }

        // Merge sorted halves (now in src) into dest
        for (int i = destLow, p = low, q = mid; i < destHigh; i++) {
            if (q >= high || p < mid && c.compare(src[p], src[q]) <= 0)
                dest[i] = src[p++];
            else
                dest[i] = src[q++];
        }
    }

    private static void swap(int[] x, int a, int b) {
        int t = x[a];
        x[a] = x[b];
        x[b] = t;
    }

Answer 2

I did try it now and it works! :)

double[] dist= {3.2, 1.4, 7.3, 2.2, 9.1}; // your array
int[] sortedIndexes= new int[dist.length]; // your array

double[] temp = dist.clone(); // clone the array
Arrays.sort(temp); // Use native array sort function

for(int i = 0; i<temp.length; i++) { // iterate through sorted array
    for(int j = 0; j<dist.length; j++) { // iterate through original array
        if (dist[j] == temp[i]) { // if sorted value == unsorted value
            sortedIndexes[i] = j; // save position of match into your sortedIndex array
        }
    }
}

Answer 3

You should customize your own Comparator and use java API.

http://docs.oracle.com/javase/6/docs/api/java/util/Arrays.html#sort(java.lang.Object[],%20int,%20int)

http://docs.oracle.com/javase/tutorial/collections/interfaces/order.html

Answer 4

You're on the right track, but

• You're better off with an Integer array than an int array if you're using a generic Comparator<Integer>.
• You have to use Arrays.sort instead Collections.sort for sorting an array.

• You have to make the distances variable final if it's referenced in an anonymous inner class.

  final double[] distances=new double[]{3.2, 1.4, 7.3, 2.2, 9.1};
  Integer[] sortedIDXs  = new Integer[]{0,1,2,3,4};
  Arrays.sort(sortedIDXs, new Comparator<Integer>() {
      public int compare(Integer idx1, Integer idx2) {
          return Double.compare(distances[idx1], distances[idx2]);
      }
  });