how to get second highest salary department wise without using analytical functions?

Question

Suppose we have 3 employees in each department.we have total 3 departments . Below is the sample source table

Emp deptno salary
A    10     1000
B    10              


        

Answer 1

Create table and insert dummy data

CREATE TABLE #Employee
(
 Id Int,
 Name NVARCHAR(10), 
 Sal int, 
 deptId int
)


INSERT INTO #Employee VALUES
(1, 'Ashish',1000,1),
(2,'Gayle',3000,1),
(3, 'Salman',2000,2),
(4,'Prem',44000,2)

Query to get result

 ;WITH cteRowNum AS (
SELECT *,
       DENSE_RANK() OVER(PARTITION BY deptId ORDER BY Sal DESC) AS RowNum
    FROM #Employee
 )
 SELECT *
 FROM cteRowNum
 WHERE RowNum = 2;

Answer 2

CREATE TABLE Employee
    ([Name] varchar(1), [Dept] varchar(1), [Salary] int)
;

INSERT INTO Employee
    ([Name], [Dept], [Salary])
VALUES
    ('a', 'M', 20),
    ('b', 'M', 25),
    ('c', 'M', 30),
    ('d', 'C', 44),
    ('e', 'C', 45),
    ('f', 'C', 46),
    ('g', 'H', 20)

Answer 3

Solution using Correlated Subquery:

SELECT * FROM emp e1 WHERE 2 = (SELECT COUNT(DISTINCT sal)
                                  FROM emp e2 
                                 WHERE e1.sal <= e2.sal
                                   AND e1.deptno = e2.deptno
                               );

Answer 4

Quite straightforward and declarative, but slow

select 
  t1.*
from 
  #tmp t1
  inner join #tmp h1 on h1.dept = t1.dept and h1.emp <> t1.emp
  left outer join #tmp h2 on h2.dept = h1.dept and h2.salary > h1.salary
  left outer join #tmp t2 on t1.dept = t2.dept and t2.salary > t1.salary and t2.emp <> h1.emp
where 
  t2.emp is null and h2.emp is null

Answer 5

Very simple logic.

Please try:

SELECT dept as dd, ( SELECT ee.salary FROM `employees` as ee WHERE ee.dept=dd 
ORDER BY ee.salary DESC LIMIT 1,1 ) as sndHigh 
FROM `employees` 
WHERE 1 
GROUP BY dept