How to broadcast in gRPC from server to client?

前端 未结 3 738
野的像风
野的像风 2021-01-06 03:26

I\'m creating a small chat application in gRPC right now and I\'ve run into the issue where if a user wants to connect to the gRPC server as a client, I\'d like to broadcast

相关标签:
3条回答
  • 2021-01-06 03:31

    Another approach is to spawn a grpc-server on client side too. On app-level you have some handshake from client to server to exchange the clients grpc-server ip and port. You probably want to create a client for that address at this point and store the client in a list.

    Now you can push messages to the clients from the list with default unary RPC calls. No [bidi] stream needed. Pros:

    • Possible to separate the clients "Push"-API from the server API.
    • Unary RPC push calls.

    Cons:

    • Additional "server". Don't know if that is possible in every scenario.
    0 讨论(0)
  • 2021-01-06 03:43

    Another option would be to use a long-polling approach. That is try something like below (code in Python, since that is what I'm most familiar with, but go should be very similar). This was not tested, and is meant to just give you an idea of how to do long-polling in gRPC:

    .PROTO defs
    -------------------------------------------------
    service Updater {
        rpc GetUpdates(GetUpdatesRequest) returns (GetUpdatesResponse);
    }
    
    message GetUpdatesRequest {
        int64 last_received_update = 1;
    }
    
    message GetUpdatesResponse {
        repeated Update updates = 1;
        int64 update_index = 2;
    }
    
    message Update {
        // your update structure
    }
    
    
    SERVER
    -----------------------------------------------------------
    class UpdaterServer(UpdaterServicer):
        def __init__(self):
            self.condition = threading.Condition()
            self.updates = []
    
        def post_update(self, update):
            """
            Used whenever the clients should be updated about something. It will
            trigger their long-poll calls to return
            """
            with self.condition:
                # TODO: You should probably remove old updates after some time
                self.updates.append(updates)
                self.condition.notify_all()
    
        def GetUpdates(self, req, context):
            with self.condition:
                while self.updates[req.last_received_update + 1:] == []:
                    self.condition.wait()
                new_updates = self.updates[req.last_received_update + 1:]
                response = GetUpdatesResponse()
                for update in new_updates:
                    response.updates.add().CopyFrom(update)
                response.update_index = req.last_received_update + len(new_updates)
                return response
    
    
    SEPARATE THREAD IN THE CLIENT
    ----------------------------------------------
    request = GetUpdatesRequest()
    request.last_received_update = -1
    while True:
        stub = UpdaterStub(channel)
        try:
            response = stub.GetUpdates(request, timeout=60*10)
            handle_updates(response.updates)
            request.last_received_update = response.update_index
        except grpc.FutureTimeoutError:
            pass
    
    0 讨论(0)
  • 2021-01-06 03:46

    Yup, I don't see any other way than keeping a global data structure containing all the connected streams and looping through them, telling each about the even that just occurred.

    0 讨论(0)
提交回复
热议问题