Python reshape a list to multidimensional list

Question

I have a list that have different length in each dimension like below:

list1=[[2,3,4],[1],[77,8,27,12],[25,15]]

and I have another list wit

Answer 1

If you want to process them in a loop, you can just do this:

list1=[[2,3,4],[1],[77,8,27,12],[25,15]]

list2=["a", "b", "c", "d", "e", "f", "g", "h", "i", "j"]

last = 0

for ele in list1:
    print(ele, list2[last : last + len(ele)])
    last += len(ele)

Result:

([2, 3, 4], ['a', 'b', 'c'])
([1], ['d'])
([77, 8, 27, 12], ['e', 'f', 'g', 'h'])
([25, 15], ['i', 'j'])

Answer 2

Flattening list1 to match list2 is easy—either just use itertools.chain.from_iterable(list)), or flat1 = [elem for sublist in list1 for elem in sublist], or the various other options in this question.

Going the other way is a bit more complicated. But, rather than looking for a one-liner, let's just do it explicitly: Create an iterator over list2, and pull elements off it as needed:

def zipstructured(list1, list2):
    iter2 = iter(list2)
    for sublist1 in list1:
        sublist2 = list(itertools.islice(iter2, len(sublist1)))
        yield sublist1, sublist2

Now you can just do this:

>>> list1=[[2,3,4],[1],[77,8,27,12],[25,15]]
>>> list2=['a','b','c','d','e','f','g','h','i','j']
>>> for sub1, sub2 in zipstructured(list1, list2):
...     print(sub1, sub2)
[2, 3, 4] ['a', 'b', 'c']
[1] ['d']
[77, 8, 27, 12] ['e', 'f', 'g', 'h']
[25, 15] ['i', 'j']

Answer 3

Here's a kind of cute way.

list1 = [[2,3,4],[1],[77,8,27,12],[25,15]]
list2 = list("abcdefghij")

list2_iterator = iter(list2)
list2_reshaped = [[next(list2_iterator) for _ in sublist] for sublist in list1]

print(list2_reshaped)

Out: [['a', 'b', 'c'], ['d'], ['e', 'f', 'g', 'h'], ['i', 'j']]

I don't know if it's possible with pure comprehensions.