How to use marshmallow to serialize a custom sqlalchemy field?

Question

I just start a simple project called flask_wiki this days and I\'m using some flask extensions as the follows:

• Flask-SQLAlchemy
• Flask-Restful

Answer 1

You need to create your own Converter. Try something like this:

import uuid
from flask_wiki.backend.models import Page
from flask_wiki.backend.backend import marsh
from marshmallow_sqlalchemy.convert import ModelConverter
from flask_wiki.backend.custom_fields import GUIDField
from marshmallow import fields


#Here you are overwriting the list of types of the SQLAlchemy, adding your custom type 
class GUIDConverter(ModelConverter):
    SQLA_TYPE_MAPPING = dict(
        list(ModelConverter.SQLA_TYPE_MAPPING.items()) + 
        [(GUIDField, fields.Str)] 
    )

class GUIDSerializationField(fields.Field):
    def _serialize(self, value, attr, obj):
        if value is None:
            return value
        else:
            if isinstance(value, uuid.UUID):
                return str(value)
            else:
                return None

class PageSchema(marsh.ModelSchema):
    class Meta:
        model = Page        
        model_converter = GUIDConverter #Tell to Marshmallow to use your custom converter for this model

    guid = GUIDSerializationField(attribute="guid")

You can also see this link for help. I hope it helped and sorry for my bad english

Answer 2

According to what I've read in the docs, you can specify a model_converter attribute in your ModelSchema Meta class. The ModelConverter class has a SQLA_TYPE_MAPPING attribute you can override in a subclass to add your custom GUID field to the types detected by the automatic schema generator.

That said, I've never used it so I don't know if this will work or not.