Getting multiple rows with prepared statement

Question

I\'m quite new to prepared statements and am not sure I am doing this right.

Here is what I try:

$currgame = 310791;

$sql = \"SELECT fk_player_id, p         


        

Answer 1

while (mysqli_stmt_fetch($stmt)) {
        printf ("%s (%s)\n", $name, $code);
    }

This might help you:

http://php.net/manual/en/mysqli-stmt.fetch.php

Answer 2

Depending on your PHP/MySQL setup you may not be able to use get_result().

The way to get around this is to bind the results.

For example:

$stmt->execute();

$fk_player_id = null; $player_tiles = null; $player_draws = null; $player_turn = null; $player_passes = null; $swapped = null;

$stmt->bind_result($fk_player_id, $player_tiles, $player_draws, $player_turn, $player_passes, $swapped);

while ($stmt->fetch()) { // For each row
    /* You can then use the variables declared above, which will have the 
    new values from the query every time $stmt->execute() is ran.*/
}

For more information click here

Answer 3

Since I don't see it in your code, make sure you're instantiating the mysqli object before trying to query on it:

$mysqli = new mysqli("127.0.0.1", "user", "password", "mydb"); 
if($mysqli->connect_error){
    die("$mysqli->connect_errno: $mysqli->connect_error");
}

Also, a ServerError would certainly show up in your logs and point you in the right direction.