How to conditionally remove first line only with sed when it matches?

Question

Can I use sed to check the first line of some command\'s output (to stdout) and delete this very first line if it matches a certain pattern?

Say, the co

Answer 1

This is what you want:

$ sed '1{/"GH"/!d}' file

Answer 2

sed '1{/<pattern>/{/GH/!d}}' input

The error in your expression can be fixed like this:

sed '1{/<pattern>/d}' input

Answer 3

You want to reference the 1st line, then say delete:

$ sed '1 d' file

No need for any pattern if you know which line you want to delete.

With a pattern, use this syntax:

$ sed '0,/pattern/ d' file

Answer 4

This might work for you:

sed -e '1!b' -e '/GH/!d' file