How do I find whether a number is positive, negative or zero without using if or for? [duplicate]

Answer 1

Try this

int status (unsigned no) {
  int sign = 0;

   // If Zero             // If -Ve = -1 OR If +Ve = -2
   (sign = ( no | 0 )) && ( sign = (~( ( (no << 1) >> 1 ) == no)) );

   // If +Ve
   (sign == -2) && (sign = 1);

  return sign;
}

Answer 2

The following will return -1 for negative values, 0 for zero, 1 for positive values of x.

int status (int x) {
  int sign = (x > 0) - (x < 0); 
  return sign;
}

Answer 3

Is this enough for your purpose?

int status(int val)
{
    int minus = (val&0x80000000)&&TRUE;
    int pos = (val&0x7FFFFFFF)&&(!(val&0x80000000));
    int r = 0 - minus + pos;
    return r;
}