Its really annoying me that I don\'t know the answer to this, I thought it would be simple. I want to get the next and previous elements from a selected element to a limit (
You can use nextAll
and prevAll
combined with the less-than :lt(index) selector
(in your case :lt(2)
)
var current = $('.active'),
next = current.nextAll(':lt(2)'),
prev = current.prevAll(':lt(2)'),
all = current.add(next).add(prev);
There are (at least) two approaches to this problem. You can chain prevAll() and nextAll() into slice(), then use add() to combine the two sets:
var $active = $("li.active");
var $around = $active.prevAll().slice(0, 2)
.add($active.nextAll().slice(0, 2));
Or you can fetch the index() of the active element, use slice()
to get siblings around that index, then filter the active element out with not():
var $active = $("li.active");
var activeIndex = $active.index();
var $around = $active.siblings().addBack()
.slice(Math.max(0, activeIndex - 2), activeIndex + 3)
.not($active);