Python: Suppressing errors from going to commandline?

Question

When I try to execute a python program from command line, it gives the following error. These errors do not cause any problem to my ouput. I dont want it to be displayed in

Answer 1

Redirect stderr to /dev/null.

python somescript.py 2> /dev/null

Answer 2

Here is a more readable, succinct solution for handling errors that are safe to ignore, without having to resort to the typical try/except/pass code block.

from contextlib import suppress

with suppress(IgnorableErrorA, IgnorableErrorB):
    do_something()

Answer 3

Doesn't catching HTMLParseError work for you? If test.py is the name of your python file, it's propagated up to there, so it should.

Here's an example how to suppress such an error. You might want to tweak it a bit to match your code.

try:
    # Put parsing code here
except HTMLParseError:
    pass

You can also just suppress the error message by redirecting stderr to null, like Ignacio suggested. To do it in code, you can just write the following:

import sys

class DevNull:
    def write(self, msg):
        pass

sys.stderr = DevNull()

However, this is probably not be what you want, because from your error it looks like the script execution is stopped, and you probably want it to be continued.

Answer 4

In python 3, @Boaz Yaniv's answer can be simplified as

sys.stderr = object

since every class in python3 is inherited from Object, so technically this would work, at least I've tried it by myself in python 3.6.5 environment.