To my surprise, a C++11 std::thread object that has finished executing, but has not yet been joined is still considered an active thread of execution. This is illustrated in
for what definition of "actively running code"? not that I know of, I'm not sure what state the thread is left in after it becomes joinable, in most cases I can think of you'd actually want fine grain control, like a flag set by the code running in that thread, anyway
for a platform specific solution, you could use GetThreadTimes
No, I don't think that this is possible. I would also try to think about your design and if such a check is really necessary, maybe you are looking for something like the interruptible threads from boost.
However, you can use std::async
- which I would do anyway - and then rely on the features std::future
provides you.
Namely, you can call std::future::wait_for with something like std::chrono::seconds(0)
. This gives you a zero-cost check and enables you to compare the std::future_status returned by wait_for
.
auto f = std::async(foo);
...
auto status = f.wait_for(std::chrono::seconds(0));
if(status == std::future_status::timeout) {
// still computing
}
else if(status == std::future_status::ready) {
// finished computing
}
else {
// There is still std::future_status::defered
}