create a generic function returning a function with the same signature

Question

In Typescript I want to create a function that will take a function and return a function with the same input-output. the function itself needs to be generic. so that it can

Answer 1

Here you go :

function f<A extends Function>(a:A):A {
    var newFunc = (...x:any[]) => {
        console.log('('+x.join(',')+') => ', a.apply(undefined, x));
        return null;
    }
    return <any>newFunc;
}

function a(j:string, k:number): boolean {
    return j === String(k);
}

var b = f(a);

b("1", 1);
b("a", 2);
b('123','123'); // ERROR