OR and AND operation in C

Question

I have a doubt in the program below.

int main()
{
    int i = -3,j = 2, k = 0,m;
    m = ++i || ++j && ++k;
    printf(\"%d %d %d %d\\n\", i, j, k, m         


        

Answer 1

Nothing after the || is evaluated, since the result of the expression ++i is nonzero.

Answer 2

You used a short circuit or. Since ++i evaluates to -2, which is not 0, it short circuits and doesn't evaluate the rest of the expression. As a result, neither j or k get incremented.

Also note that the short circuit operators, || and &&, are left associative and that || is higher precedence than &&. As a result, the || gets evaluated first, and early outs if the left hand side evaluates to true, while && early outs if the left hand side evaluates to false.

EDIT: Fixed a mistake with explaining the precedence.