str_word_count() for non-latin words?

Question

im trying to count the number of words in variable written in non-latin language (Bulgarian). But it seems that str_word_count() is not counting non-latin words. The encodin

Answer 1

And here is the solution that come to my mind:

$var = "текст на кирилица с пет думи";
$array = explode(" ", $var);

$i = 0;
foreach($array as $item) 
    {
    if(strlen($item) > 2) $i++ ;
    }

echo $i; // will return 5

Answer 2

As it stated in str_word_count description

'word' is defined as a locale dependent string

Specify Bulgarian locale before calling str_word_count

setlocale(LC_ALL, 'bg_BG');
echo str_word_count($content);

Read more about setlocale here.

Answer 3

You may do it with regex:

$str = "текст на кирилица";
echo 'Number of words: '.count(preg_split('/\s+/', $str));

here I'm defining word delimiter as space characters. If there may be something else that will be treated as word delimiter, you'll need to add it into your regex.

Also, note, that since there's no utf characters in regex (not in string) - /u modifier isn't required. But if you'll want some utf characters to act as delimiter, you'll need to add this regex modifier.

Update:

If you want only cyrillic letters to be treated in words, you may use:

$str = "текст 
на 12453
кирилица";
echo 'Number of words: '.count(preg_split('/[^А-Яа-яЁё]+/u', $str));

Answer 4

The best solution I found is to provide a list of characters for word count function:

$text = 'текст на кирилице and on english too';
$count = str_word_count($text, 0, 'АБВГДЕЁЖЗИЙКЛМНОПРСТУФХЦЧШЩЪЫЬЭЮЯабвгдеёжзийклмнопрстуфхцчшщъыьэюя');
echo $count; // => 7