jQuery: replace() in html()

Question

How can I replace html parts with replace()?

    google.com



        

Answer 1

Make your pattern global by using the g switch:

var e = $("div"),
fix = e.html().replace(/google.com/g, "duckduckgo.com");
e.html(fix);

jsFiddle example

This way it replaces the link and the text.

Answer 2

The problem is that .replace only replaces first occurence. If you want to replace all occurences, you must use a regular expression with a g (global) flag:

var e = $("div"),
    fix = e.html().replace(/google\.com/g, "duckduckgo.com");
e.html(fix);

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div>
    <a href="http://www.google.com">google.com</a>
</div>

Demo

Remember you must escape special characters such as ., though. If you prefer, you can use

String.prototype.replaceAll = function(s1, s2) {
    return this.replace(
        new RegExp(  s1.replace(/[.^$*+?()[{\|]/g, '\\$&'),  'g'  ),
        s2
    );
};

var e = $("div"),
    fix = e.html().replaceAll('google.com', "duckduckgo.com");
e.html(fix);

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.0.2/jquery.min.js"></script>
<div>
    <a href="http://www.google.com">google.com</a>
</div>

Demo

Answer 3

$("div a").attr("href", function (i, o) {
    return (/google/.test(o) ? "http://duckduckgo.com" : o)
}).html($("a", this).attr("href").substr(7))

jsfiddle http://jsfiddle.net/guest271314/6rrKs/