How to I properly set UIColor from int?

Question

I am trying to set the textColor of a UITextView by assigning it a value.

Earlier in the program I have

textView.textColor         


        

Answer 1

as par you submited answer this is not an answer UIColorFromRGB is a Macro that define above at @implementation like

#define UIColorFromRGB(rgbValue) [UIColor colorWithRed:((float)((rgbValue & 0xFF0000) >> 16))/255.0 green:((float)((rgbValue & 0xFF00) >> 8))/255.0 blue:((float)(rgbValue & 0xFF))/255.0 alpha:1.0];

Then you can use like

textView.textColor = UIColorFromRGB(0x888888);

you can use its property of UIColor for setting color of text bg-color etc in objective c

Answer 2

You can do this by following these steps:

1. Do convert hex value to RGB use HexToRGB.

2. And then change the text color of your textview by doing this :

    textview.textColor = [UIColor colorWithRed:244/255.00f
       green:133/255.00f blue:116/255.00f alpha:1.0f]; // values are just an example
   

Answer 3

I figured out you can use UIColorFromRGB() to convert it to a UIColor.

e.g.

textView.textColor = UIColorFromRGB(0x888888);

Answer 4

Swift extension version

public extension UIColor {
public convenience init<T>(rgbValue: T, alpha: CGFloat = 1) where T: BinaryInteger {
    guard rgbValue > 0 else {
        self.init(red: 0, green: 0, blue: 0, alpha: alpha)
        return
    }

    guard rgbValue < 0xFFFFFF else {
        self.init(red: 1, green: 1, blue: 1, alpha: alpha)
        return
    }

    let r: CGFloat = CGFloat(((rgbValue & 0xFF0000) >> 16) / 0xFF)
    let g: CGFloat = CGFloat((rgbValue & 0x00FF00) >> 8 / 0xFF)
    let b: CGFloat = CGFloat((rgbValue & 0x0000FF) / 0xFF)

    self.init(red: r, green: g, blue: b, alpha: alpha)
}

}

usage:

let white =  UIColor(rgbValue: 16777215)
let red =    UIColor(rgbValue: 16711680)
let green =  UIColor(rgbValue: 0x00FF00)
let blue =   UIColor(rgbValue: 0x0000FF)
let yellow = UIColor(rgbValue: 0xFFFF00)
let black =  UIColor(rgbValue: 0)

Answer 5

Swift version

You can use the following function to convert a RGB hexadecimal color Int to a UIColor.

func uiColorFromHex(rgbValue: Int) -> UIColor {
    
    // &  binary AND operator to zero out other color values
    // >>  bitwise right shift operator
    // Divide by 0xFF because UIColor takes CGFloats between 0.0 and 1.0
    
    let red =   CGFloat((rgbValue & 0xFF0000) >> 16) / 0xFF
    let green = CGFloat((rgbValue & 0x00FF00) >> 8) / 0xFF
    let blue =  CGFloat(rgbValue & 0x0000FF) / 0xFF
    let alpha = CGFloat(1.0)
    
    return UIColor(red: red, green: green, blue: blue, alpha: alpha)
}

And can be used like this

let myColorValue = 0x888888
let color = uiColorFromHex(myColorValue)

Answer 6

it was necessary to use

textView.textColor = [UIColor colorWithRed:<#(CGFloat)#> green:<#(CGFloat)#> blue:<#(CGFloat)#> alpha:<#(CGFloat)#>];

try it:

- (UIColor *)UIColorFromRGB:(NSInteger)rgbValue {
    return [UIColor colorWithRed:((float)((rgbValue & 0xFF0000) >> 16))/255.0
                           green:((float)((rgbValue & 0xFF00) >> 8))/255.0
                            blue:((float)(rgbValue & 0xFF))/255.0
                           alpha:1.0];
}

...

textView.textColor = [self UIColorFromRGB:0x888888];