how is the correct way to use copy_from_user?

Question

I am trying to copy a value from user space to kernel space with the function:

static ssize_t device_write(struct file *filp, const char *buff, size_t len, l         


        

Answer 1

The write function prototype in the manual is:

ssize_t write(int fd, const void *buf, size_t count);

So you only need to pass 3 values to write, namely: the file descriptor fd, buffer where your data lies, and count of bytes you want to write.

This regarding the user space. Now let's move to the kernel space write function, i.e. your device_write.

The argument buf to this function is the one which contains data which you want to write from user space, count is the length of data sent to be written by the kernel. So you are supposed to copy data from buf pointer and not len.

So, the correct way would be:

char *desp;  //allocate memory for this in kernel using malloc
copy_from_user (desp, buff, len);

This should do.

Answer 2

len does not exist in user-space. It is passed by value, so len is accessible as a normal variable in kernel-space. desp = (int)len is all you need. Note, however, that size_t is not the same as int, and on 64-bit platforms size_t is 8 bytes.

copy_from_user() is for the buffer you're trying to write (called buffer in your user-space code, and buff in your kernel-space argument list). What's passed is a pointer to a memory address which only exists in user-space, so copy_from_user() copies that buffer to a kernel-space buffer.