Suppose I want to apply a function to each row of a matrix. One of the function\'s arguments takes a vector. I would like to apply the first element of the vector to the fir
As there are two arguments that should be the corresponding rows and elements in matrix/vector respectively, we can loop through the sequence of rows, subset the data and apply the function
sapply(seq_len(nrow(df)), function(i) MYFUNC(df[i,], Var = var2[i]))
#[1] 5.0795111 2.8693537 1.8285747 1.3640238 0.8300597 0.6280441
#[7] 0.7706310 0.6720132 0.5719003 0.4259674
For the specific example, it can be vectorized with rowSums
rowSums(df)/var2
#[1] 5.0795111 2.8693537 1.8285747 1.3640238 0.8300597 0.6280441
#[7] 0.7706310 0.6720132 0.5719003 0.4259674
Mapply
is definitely a possibility. This should work:
mapply(MYFUNC, x = as.data.frame(t(df)), Var = var2)
#V1 V2 V3 V4 V5 V6 V7 V8 V9 V10
#5.0795111 2.8693537 1.8285747 1.3640238 0.8300597 0.6280441 0.7706310 0.6720132 0.5719003 0.4259674
The issue I think you were running into is that mapply
takes either vectors or lists. In R matrices aren't lists, but data.frame
s are. All you need to do is transpose your matrix and convert to a data.frame
and then mapply
should work. Each column in a data.frame
is an element in the list which is why we have to transpose it (so that each row
will be mapped to each element in the vector).