How to force std::stringstream operator >> to read an entire string instead of stopping at the first whitespace?
I\'ve got a template class that stores a value read
There isn't a way with operator>> that I'm aware of excepted writing your own facet (operator>> stop at first character for which isspace(c, getloc()) is true). But there is a getline function in <string> which has the behaviour you want.
Where do you want it to stop? If you want to read a whole line you probably need getline function, if you need an entire string stored in the streamstring object your choise is ostringstream::str method.
As operator >> is not satisfying our requirement when T=string, we can write a specific function for [T=string] case. This may not be the correct solution. But, as a work around have mentioned.
Please correct me if it won't satisfy your requirement.
I have written a sample code as below:
#include <iostream>
#include <sstream>
#include <string>
using namespace std;
template <class T>
class Data
{
T m_value;
public:
void set(const T& val);
T& get();
};
template <class T>
void Data<T>::set(const T& val)
{
stringstream ss;
ss << val;
ss >> m_value;
}
void Data<string>::set(const string& val)
{
m_value = val;
}
template <class T>
T& Data<T>::get()
{
return m_value;
}
int main()
{
Data<int> d;
d.set(10);
cout << d.get() << endl;
Data<float> f;
f.set(10.33);
cout << f.get() << endl;
Data<string> s;
s.set(string("This is problem"));
cout << s.get() << endl;
}
If you can use Boost then use boost::lexical_cast.
I'm assuming you're instantiating that template with T = std::string
. In that case you could use getline:
getline(ss, m_value, '\0');
However, this assumes you won't accept nul-characters as valid parts of the string.
Otherwise you can write your own extractor for `T'.
Here is a solution :
std::istream & ReadIntoString (std::istream & istr, std::string & str)
{
std::istreambuf_iterator<char> it(istr), end;
std::copy(it, end, std::inserter(str, str.begin()));
return istr;
}
(Thanks to the original poster in C++ newsgroup)