MySQL select DISTINCT by highest value

Question

I have a table full of magazines, and need to extract the latest unique issue of each magazine.

Ive tried

    SELECT DISTINCT
    magazine
        F         


        

Answer 1

SELECT id, MAX(onSale) as latest, magazine
FROM product
GROUP BY magazine
ORDER BY latest DESC

Answer 2

None of the given answers are correct, as they return an disassociated set of data that does not represent one exact column. The id may not be the id from the same row as the onsale value.

The following will work:

SELECT
    id, onsale, magazine
FROM (
    SELECT
       id, onsale, magazine
    FROM
        product
    ORDER BY
        onsale DESC) AS a
GROUP BY
    magazine

Answer 3

You need to put the 'rest of data' in the first select:

SELECT DISTINCT magazine, "rest of data"
FROM product p 
INNER JOIN 
( SELECT title, MAX(onSale) AS Latest 
FROM product 
GROUP BY magazine ) groupedp

Answer 4

SELECT 
    p.*
FROM
        product p
    INNER JOIN
        ( SELECT 
              magazine, MAX(onSale) AS latest
          FROM
              product
          GROUP BY 
              magazine
        ) AS groupedp
      ON  groupedp.magazine = p.magazine
      AND groupedp.latest = p.onSale ;

Answer 5

This looks like what you need:

SELECT id, MAX(onsale) AS onsale, magazine FROM magazines GROUP BY magazine ORDER BY onsale DESC;

Check it out at:

http://sqlfiddle.com/#!2/38e78/3

UPDATE: I've changed query a little, to return MAX(onsale)