Convert character to the corresponding virtual-key code

Question

Currently, I\'m using the method VkKeyScan in the Win32 API to convert a character to its virtual-key code. But the problem that this seems to have is that, whe

Answer 1

You should be clearer in what your requirements are, more specifically in what you consider to be an appropriate key code. The VkKeyScan as specified in it's documentation returns the virtual-key code in the low-order byte and the shift state in the high-byte of the return value.

This is demonstrated in the code snippet below that uses the '(' character as input for the VkKeyScan method.

[DllImport("user32.dll")]static extern short VkKeyScan(char ch);

static void Main(string[] args)
{
    var helper = new Helper { Value = VkKeyScan('(') };

    byte virtualKeyCode = helper.Low;
    byte shiftState = helper.High;

    Console.WriteLine("{0}|{1}", virtualKeyCode, (Keys)virtualKeyCode);
    Console.WriteLine("SHIFT pressed: {0}", (shiftState & 1) != 0);
    Console.WriteLine("CTRL pressed: {0}", (shiftState & 2) != 0);
    Console.WriteLine("ALT pressed: {0}", (shiftState & 4) != 0);
    Console.WriteLine();

    Keys key = (Keys)virtualKeyCode;

    key |= (shiftState & 1) != 0 ? Keys.Shift : Keys.None;
    key |= (shiftState & 2) != 0 ? Keys.Control : Keys.None;
    key |= (shiftState & 4) != 0 ? Keys.Alt : Keys.None;

    Console.WriteLine(key);
    Console.WriteLine(new KeysConverter().ConvertToString(key));
}

[StructLayout(LayoutKind.Explicit)]
struct Helper
{
    [FieldOffset(0)]public short Value;
    [FieldOffset(0)]public byte Low;
    [FieldOffset(1)]public byte High;
}

Running this snippet will result in the following output:

// 56|D8
// SHIFT pressed: True
// CTRL pressed: False
// ALT pressed: False
// 
// D8, Shift
// Shift+8