I want to unflatten an object like this...
var obj2 = {
\"firstName\": \"John\",
\"lastName\": \"Green\",
\"car.make\": \"Honda\",
\"car.mode
Try breaking the problem down into two distinct challenges:
You might start with a setIn
function that would look something like this:
function setIn(path, object, value) {
let [key, ...keys] = path;
if (keys.length === 0) {
object[key] = value;
} else {
let nextKey = keys[0];
object[key] = object[key] || isNaN(nextKey) ? {} : [];
setIn(keys, object[key], value);
}
return object;
}
Then combine it with an unflatten
function which loops over an object running setIn
for each key.
function unflatten(flattened) {
let object = {};
for (let key in flattened) {
let path = key.split('.');
setIn(path, object, flattened[key]);
}
return object;
}
Of course, there's already an npm package for doing this, and it'd also it'd be easy to implement your own using functions like _.set from lodash.
It's unlikely that you'd ever run into a long enough path that you'd end up running out of stack frames, but of course it's possible to implement setIn
without recursion, using loops or trampolines.
And finally, if immutable data is your thing and you want to work with a version of setIn
that doesn't modify your data structures, then you could take a look at the implementation in Zaphod—a JavaScript library for treating the native data structures as though they were immutable.
You can first use for...in
loop to loop object properties, then split each key at .
then use reduce to build nested properties.
var obj2 = {"firstName":"John","lastName":"Green","car.make":"Honda","car.model":"Civic","car.revisions.0.miles":10150,"car.revisions.0.code":"REV01","car.revisions.0.changes":"","car.revisions.1.miles":20021,"car.revisions.1.code":"REV02","car.revisions.1.changes.0.type":"asthetic","car.revisions.1.changes.0.desc":"Left tire cap","car.revisions.1.changes.1.type":"mechanic","car.revisions.1.changes.1.desc":"Engine pressure regulator","visits.0.date":"2015-01-01","visits.0.dealer":"DEAL-001","visits.1.date":"2015-03-01","visits.1.dealer":"DEAL-002"}
function unflatten(data) {
var result = {}
for (var i in data) {
var keys = i.split('.')
keys.reduce(function(r, e, j) {
return r[e] || (r[e] = isNaN(Number(keys[j + 1])) ? (keys.length - 1 == j ? data[i] : {}) : [])
}, result)
}
return result
}
console.log(unflatten(obj2))
You could walk the splitted substrings
and a temporary object with a check if the key exists and build a new property with a check for the next property if it is a finite number, then assign an array, otherwise an object. At last assign with the last substring the value to the temp object.
function unflatten(obj) {
var result = {}, temp, substrings, property, i;
for (property in obj) {
substrings = property.split('.');
temp = result;
for (i = 0; i < substrings.length - 1; i++) {
if (!(substrings[i] in temp)) {
if (isFinite(substrings[i + 1])) { // check if the next key is
temp[substrings[i]] = []; // an index of an array
} else {
temp[substrings[i]] = {}; // or a key of an object
}
}
temp = temp[substrings[i]];
}
temp[substrings[substrings.length - 1]] = obj[property];
}
return result;
};
var obj2 = { "firstName": "John", "lastName": "Green", "car.make": "Honda", "car.model": "Civic", "car.revisions.0.miles": 10150, "car.revisions.0.code": "REV01", "car.revisions.0.changes": "", "car.revisions.1.miles": 20021, "car.revisions.1.code": "REV02", "car.revisions.1.changes.0.type": "asthetic", "car.revisions.1.changes.0.desc": "Left tire cap", "car.revisions.1.changes.1.type": "mechanic", "car.revisions.1.changes.1.desc": "Engine pressure regulator", "visits.0.date": "2015-01-01", "visits.0.dealer": "DEAL-001", "visits.1.date": "2015-03-01", "visits.1.dealer": "DEAL-002" };
console.log(unflatten(obj2));
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A slightly more compact version could be this
function unflatten(object) {
var result = {};
Object.keys(object).forEach(function (k) {
setValue(result, k, object[k]);
});
return result;
}
function setValue(object, path, value) {
var way = path.split('.'),
last = way.pop();
way.reduce(function (o, k, i, kk) {
return o[k] = o[k] || (isFinite(i + 1 in kk ? kk[i + 1] : last) ? [] : {});
}, object)[last] = value;
}
var obj2 = { "firstName": "John", "lastName": "Green", "car.make": "Honda", "car.model": "Civic", "car.revisions.0.miles": 10150, "car.revisions.0.code": "REV01", "car.revisions.0.changes": "", "car.revisions.1.miles": 20021, "car.revisions.1.code": "REV02", "car.revisions.1.changes.0.type": "asthetic", "car.revisions.1.changes.0.desc": "Left tire cap", "car.revisions.1.changes.1.type": "mechanic", "car.revisions.1.changes.1.desc": "Engine pressure regulator", "visits.0.date": "2015-01-01", "visits.0.dealer": "DEAL-001", "visits.1.date": "2015-03-01", "visits.1.dealer": "DEAL-002" };
console.log(unflatten(obj2));
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