How to delete duplicated rows based in a column value?

Question

Given the following table

 123456.451 entered-auto_attendant
 123456.451 duration:76 real:76
 139651.526 entered-auto_attendant
 139651.526 duration:62 real:         


        

Answer 1

you didn't give an expected output, does this work for you?

 awk '!a[$1]++' file

with your data, the output is:

123456.451 entered-auto_attendant
139651.526 entered-auto_attendant
139382.537 entered-auto_attendant

and this line prints only unique column1 line:

 awk '{a[$1]++;b[$1]=$0}END{for(x in a)if(a[x]==1)print b[x]}' file

output:

139382.537 entered-auto_attendant

Answer 2

uniq, by default, compares the entire line. Since your lines are not identical, they are not removed.

You can use sort to conveniently sort by the first field and also delete duplicates of it:

sort -t ' ' -k 1,1 -u file

• -t ' ' fields are separated by spaces
• -k 1,1: only look at the first field
• -u: delete duplicates

Additionally, you might have seen the awk '!a[$0]++' trick for deduplicating lines. You can make this dedupe on the first column only using awk '!a[$1]++'.

Answer 3

try this command

awk '!x[$1]++ { print $1, $2 }' file

Answer 4

Using awk:

awk '!($1 in a){a[$1]++; next} $1 in a' file
123456.451 duration:76 real:76
139651.526 duration:62 real:62