Get `Meta` attribute `content` by selecting `property` attribute

Question

In jQuery you can do this:

$(\"meta[property=\'fb:app_id\']\").attr(\"content\");

Which will give you the content attribute va

Answer 1

document.querySelector('meta[property~="fb:app_id"][content]').content

Answer 2

Not as elegant as JQuery I'm afraid...

var metaTags=document.getElementsByTagName("meta");

var fbAppIdContent = "";
for (var i = 0; i < metaTags.length; i++) {
    if (metaTags[i].getAttribute("property") == "fb:app_id") {
        fbAppIdContent = metaTags[i].getAttribute("content");
        break;
    }
}

console.log(fbAppIdContent);

Answer 3

Note: Some use the property attribute:

<meta property="fb:app_id" content="1234567890">

whereas others use the name attribute:

 <meta name="fb:app_id" content="1234567890">

I use the following to get the value from both variants:

var appId = (function(c) { for (var a = document.getElementsByTagName("meta"), b = 0;b < a.length;b++) {
  if (c == a[b].name || c == a[b].getAttribute("property")) { return a[b].content; } } return false;
})("fb:app_id");

console.log(appId); //(bool)false if meta tag "fb:app_id" not exists.

---

The same can be used for every other meta tag as well - just change the input value on the closure function (eg. from fb:app_id to description).

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Edit: Or as a more generic function:

function getContentByMetaTagName(c) {
  for (var b = document.getElementsByTagName("meta"), a = 0; a < b.length; a++) {
    if (c == b[a].name || c == b[a].getAttribute("property")) { return b[a].content; }
  } return false;
}

console.log(getContentByMetaTagName("og:title"));