I want to read the raw binary of a file and put it into a string. Currently I am opening a file with the \"rb\" flag and printing the byte but it\'s coming up as ASCII chara
to get the binary representation I think you will need to import binascii, then:
byte = f.read(1)
binary_string = bin(int(binascii.hexlify(byte), 16))[2:].zfill(8)
or, broken down:
import binascii
filePath = "mysong.mp3"
file = open(filePath, "rb")
with file:
byte = file.read(1)
hexadecimal = binascii.hexlify(byte)
decimal = int(hexadecimal, 16)
binary = bin(decimal)[2:].zfill(8)
print("hex: %s, decimal: %s, binary: %s" % (hexadecimal, decimal, binary))
will output:
hex: 64, decimal: 100, binary: 01100100
What you are reading IS really the "raw binary" content of your "binary" file. Strange as it might seems, binary data are not "0's and 1's" but binary words (aka bytes, cf http://en.wikipedia.org/wiki/Byte) which have an integer (base 10) value and can be interpreted as ascii chars. Or as integers (which is how one usually do binary operations). Or as hexadecimal. For what it's worth, "text" is actually "raw binary data" too.
To get a "binary" representation you can have a look here : Convert binary to ASCII and vice versa but that's not going to give you more "raw binary data" than what you actually have...
Now the question: why do you want these data as "0's and 1's" exactly ?