I have created a piece of code this:
intToDigit :: Char -> Int
ord :: Char -> Int
intToDigit c = ord c - ord \'a\'
However, when I ru
You need to provide an implementation for the function ord
. Here, you have given a signature for ord
, but no implementation.
Or you can use Haskell's own ord
function, that is Char.ord
.
Remove the line:
ord :: Char -> Int
Or give it a definition.
And it's a bad idea to name your function intToDigit, while it's already used in Data.Char to do the opposite of what you are doing.
Your function is Data.Char.digitToInt, and its implementation also works with hexadecimal:
digitToInt :: Char -> Int
digitToInt c
| isDigit c = ord c - ord '0'
| c >= 'a' && c <= 'f' = ord c - ord 'a' + 10
| c >= 'A' && c <= 'F' = ord c - ord 'A' + 10
| otherwise = error ("Char.digitToInt: not a digit " ++ show c) -- sigh
Actually it's not what you defined... why 'a'
in your code?