add filename to beginning of file using find and sed

Question

using the following I add the file name to the front of each line and send the output to a single file.

ls | while read file; do sed -e \"s/^/$file/g\" $fil         


        

Answer 1

Why don't you simply replace the ls in your first line with the find like this?

find . -type f | while read file; do sed -e "s|^|$file|" $file > out; done

You must only exchange the delimiter for s from / to something else not contained in your filenames. I have chosen | as an example.

Answer 2

this one works fine for me and it is simpler to use than Kent's answer
NOTE: than the full pathname is inserted for that one

find . -type f | xargs -r -t -i sed -r 's|^|'{}' |g' {}

use this one instead to keep only the bare filename part

find . -type f | xargs -r -t -i sed -r -e 's|^|'{}' |g' -e 's|^.+/||g' {}

then if your are happy with stdout results you might add -i switch to the sed command to overwrite the files

find . -type f | xargs -r -t -i sed -i -r -e 's|^|'{}' |g' -e 's|^.+/||g' {}

Answer 3

How about:

find . -type f | xargs -i echo FILE/{} > out

Answer 4

untested, try using xargs

find . -type f | xargs -I FILE sed "s/^/FILE/g" FILE > out

Answer 5

 find . -type f |xargs awk '$0=FILENAME$0' > out

as I answered this, your "no awk" line not yet there. anyway, take a look my updated answer below:

updated based on comment

so you want to use find, exec/xargs, and sed to do it. My script needs GNU Sed, i hope you have it.

see the one liner first: (well, > out is omitted. You could add it to the end of the line. )

find . -type f | xargs -i echo {}|sed -r 's#(.\/)(.*)#cat &\|sed  "s:^:file \2 :g"#ge'

now let's take a test, see below:

kent$  head *.txt
==> a.txt <==
A1
A2

==> b.txt <==
B1
B2

kent$  find . -type f | xargs -i echo {}|sed -r 's#(.\/)(.*)#cat &\|sed  "s:^:file \2 :g"#ge'
file b.txt B1
file b.txt B2
file a.txt A1
file a.txt A2

is the result your expectation?

Short explanation

• find ....|xargs -i echo {} nothing to explain, just print the filename per line (with leading "./")
• then pass the filename to a sed line like sed -r 's#(.\/)(.*)# MAGIC #ge'
• remember that in the above line, we have two groups \1: "./" and \2 "a.txt"(filename)
• since we have e at the end of sed line, the MAGIC part would be executed as shell command.(GNU sed needed)
• MAGIC: cat &\|sed "s:^:file \2 :g cat & is just output the file content, and pipe to another sed. do the replace (s:..:..:g)
• finally, the execution result of MAGIC would be the Replacement of the outer sed.

the key is the 'e' of Gnu sed.