Multiple optional arguments python

Question

So I have a function with several optional arguments like so:

def func1(arg1, arg2, optarg1=None, optarg2=None, optarg3=None):

Optarg1 &

Answer 1

**kwargs is used to let Python functions take an arbitrary number of keyword arguments and then ** unpacks a dictionary of keyword arguments. Learn More here

def print_keyword_args(**kwargs):
    # kwargs is a dict of the keyword args passed to the function
    print kwargs
    if("optarg1" in kwargs and "optarg2" in kwargs):
        print "Who needs optarg3!"
        print kwargs['optarg1'], kwargs['optarg2']
    if("optarg3" in kwargs):
        print "Who needs optarg1, optarg2!!"
        print kwargs['optarg3']

print_keyword_args(optarg1="John", optarg2="Doe")
# {'optarg1': 'John', 'optarg2': 'Doe'}
# Who needs optarg3!
# John Doe
print_keyword_args(optarg3="Maxwell")
# {'optarg3': 'Maxwell'}
# Who needs optarg1, optarg2!!
# Maxwell
print_keyword_args(optarg1="John", optarg3="Duh!")
# {'optarg1': 'John', 'optarg3': 'Duh!'}
# Who needs optarg1, optarg2!!
# Duh!

Answer 2

If you assign them in the call of the function you can pre-empt which parameter you are passing in.

def foo( a, b=None, c=None):
    print("{},{},{}".format(a,b,c))

>>> foo(4) 
4,None,None
>>> foo(4,c=5)
4,None,5