Java: how to convert a List<?> to a Map<String,?> [duplicate]

Answer 1

Using reflection and generics:

public static <T> Map<String, T> MapMe(Class<T> clz, Collection<T> list, String methodName)
throws Exception{
  Map<String, T> map = new HashMap<String, T>();
  Method method = clz.getMethod(methodName);
  for (T el : list){
    map.put((String)method.invoke(el), el);
  }
  return map;
}

In your documentation, make sure you mention that the return type of the method must be a String. Otherwise, it will throw a ClassCastException when it tries to cast the return value.

Answer 2

If you're sure that each object in the List will have a unique index, use Guava with Jorn's suggestion of Maps.uniqueIndex.

If, on the other hand, more than one object may have the same value for the index field (which, while not true for your specific example perhaps, is true in many use cases for this sort of thing), the more general way do this indexing is to use Multimaps.index(Iterable<V> values, Function<? super V,K> keyFunction) to create an ImmutableListMultimap<K,V> that maps each key to one or more matching values.

Here's an example that uses a custom Function that creates an index on a specific property of an object:

List<Foo> foos = ...
ImmutableListMultimap<String, Foo> index = Multimaps.index(foos,
    new Function<Foo, String>() {
      public String apply(Foo input) {
        return input.getBar();
      }
    });

// iterate over all Foos that have "baz" as their Bar property
for (Foo foo : index.get("baz")) { ... }

Answer 3

Here's what I would do. I am not entirely sure if I am handling generics right, but oh well:

public <T> Map<String, T> mapMe(Collection<T> list) {
   Map<String, T> map = new HashMap<String, T>();
   for (T el : list) {
       map.put(el.toString(), el);
   }   
   return map;
}

Just pass a Collection to it, and have your classes implement toString() to return the name. Polymorphism will take care of it.

Answer 4

Java 8 streams and method references make this so easy you don't need a helper method for it.

Map<String, Foo> map = listOfFoos.stream()
    .collect(Collectors.toMap(Foo::getName, Function.identity()));

If there may be duplicate keys, you can aggregate the values with the toMap overload that takes a value merge function, or you can use groupingBy to collect into a list:

//taken right from the Collectors javadoc
Map<Department, List<Employee>> byDept = employees.stream()
    .collect(Collectors.groupingBy(Employee::getDepartment));

As shown above, none of this is specific to String -- you can create an index on any type.

If you have a lot of objects to process and/or your indexing function is expensive, you can go parallel by using Collection.parallelStream() or stream().parallel() (they do the same thing). In that case you might use toConcurrentMap or groupingByConcurrent, as they allow the stream implementation to just blast elements into a ConcurrentMap instead of making separate maps for each thread and then merging them.

If you don't want to commit to Foo::getName (or any specific method) at the call site, you can use a Function passed in by a caller, stored in a field, etc.. Whoever actually creates the Function can still take advantage of method reference or lambda syntax.

Answer 5

Using Guava (formerly Google Collections):

Map<String,Role> mappedRoles = Maps.uniqueIndex(yourList, Functions.toStringFunction());

Or, if you want to supply your own method that makes a String out of the object:

Map<String,Role> mappedRoles = Maps.uniqueIndex(yourList, new Function<Role,String>() {
  public String apply(Role from) {
    return from.getName(); // or something else
  }});

Answer 6

Avoid reflection like the plague.

Unfortunately, Java's syntax for this is verbose. (A recent JDK7 proposal would make it much more consise.)

interface ToString<T> {
    String toString(T obj);
}

public static <T> Map<String,T> stringIndexOf(
    Iterable<T> things,
    ToString<T> toString
) {
    Map<String,T> map = new HashMap<String,T>();
    for (T thing : things) {
        map.put(toString.toString(thing), thing);
    }
    return map;
}

Currently call as:

Map<String,Thing> map = stringIndexOf(
    things,
    new ToString<Thing>() { public String toString(Thing thing) {
        return thing.getSomething();
    }
);

In JDK7, it may be something like:

Map<String,Thing> map = stringIndexOf(
    things,
    { thing -> thing.getSomething(); }
);

(Might need a yield in there.)