Java regex throwing exception for no match found when pattern found in line

Question

I am dying trying to figure out why a regex won\'t match. Any help is much appreciated. I\'m going line by line of a web page (that works fine), but I need to pull out the l

Answer 1

Ok, so I figured it out. The only issue was, my regex had to be

".*href=\"([^\"]*?)\".*"

Which then made the code

private String regex = ".*href=\"([^\"]*?)\".*";
private Pattern p = Pattern.compile(regex);
Matcher m = p.matcher(result);
if (m.matches()) {
    String urlStr = m.group(1);
    links.add(urlStr);
}

So that was my issue with the regex, I had to use the '?' to not be greedy I guess!

Answer 2

first call

m.find();

or

m.matches();

and then you'll be able to use m.group() if matcher succeeded.