LINQ: …Where(x => x.Contains(string that start with “foo”))

Question

Given a collection of the following class:

public class Post
{
    ...
    public IList Tags { get; set; }
}

Is there an easy

Answer 1

Use string's StartsWith

var postsWithFooTag = posts.Where(x => x.Tags.Any(y => y.StartsWith("foo")));

x.Any will check if any element matches some condition. StartsWith checks if the element starts with a certain string.

The above returned:

new Post { Tags = new[] { "fooTag", "tag" }},
new Post { Tags = new[] { "someTag", "fooBarTag" }}

To make it case insensitive use StringComparison.OrdinalIgnoreCase.

var postsWithFooTag = posts.Where(x => x.Tags.Any(y => y.StartsWith("FoO", StringComparison.OrdinalIgnoreCase)));

Returns:

new Post { Tags = new[] { "fooTag", "tag" }},
new Post { Tags = new[] { "someTag", "fooBarTag" }}

while StartsWith("FoO") returns no results.

Answer 2

I believe this will work for what you're trying to do.

posts.Where(p => p.Tags.Any(t => t.StartsWith("foo")))

Answer 3

var tag = "foo";
var postsWithFooTag = 
  posts.Where( p=> p.Tags.Any( t => t.StartsWith(tag)));

Answer 4

Try this:

var postsWithFooTag = posts.Where(x => x.Tags.Any(y => y.StartsWith("foo")))

Answer 5

Try x => x.Tags.Any(tag => tag.StartsWith("foo"))