How can I strip the data:image part from a base64 string of any image type in PHP

Question

I am currently doing the following to decode base64 images in PHP:

   $img = str_replace(\'data:image/jpeg;base64,\', \'\', $s[\'image\']);
   $img = str_rep         


        

Answer 1

I generete a image with javascript/kendo and send this by ajax to the server.

preg_replace('#^data:image/[^;]+;base64,#', '', $s['image']); 

it does not work in this case. in my case this code works better:

$contentType  = mime_content_type($s['image']);
$img = preg_replace('#^data:image/(.*?);base64,#i', '$2', $s['image']);

Answer 2

Function file_get_contents remove header and use base64_decode function, so you get clear content image.

Try this code:

$img = 'data:image/png;base64,iVBORw0KGgoAAAANSUhEUgAAA0gA...';
$imageContent = file_get_contents($img);

Answer 3

You would have to test it but I think this solution should be slightly faster than Mihai Iorga's

$offset = str_pos($s['image'], ',');
$data = base64_decode(substr($s['image'], $offset));

Answer 4

You can Regular expression for remove image or pdf data formate.

data.replace(/^data:application\/[a-z]+;base64,/, "")

Answer 5

You can use a regular expression:

$img = preg_replace('#data:image/[^;]+;base64,#', '', $s['image']);

if the text you are replacing is the first text in the image, adding ^ at the beginning of the regexp will make it much faster, because it won't analyze the entire image, just the first few characters:

$img = preg_replace('#^data:image/[^;]+;base64,#', '', $s['image']);