Double.TryParse() input decimal separator different than system decimal separator

Question

I have a source XML that uses a dot (\".\") as a decimal separator and I am parsing this on a system that uses a comma (\",\") as a decimal separator.

As a result,

Answer 1

double.TryParsehas an overload taking an IFormatProvider. Use a coresponding CultureInfo, in your case CultureInfo.InvariantCulture can be used.

Answer 2

This does the job:

    string test = "0.7";
    Assert.Equal(0.7, Double.Parse(test, NumberStyles.Float, CultureInfo.InvariantCulture));

Answer 3

Easy way to specify custom decimal separator:

var price = "122$00";
var nfi = new NumberFormatInfo { CurrencyDecimalSeparator = "$" };
var ok = decimal.TryParse(price, NumberStyles.Currency, nfi, out result);

Answer 4

XML standard is explicit about the formatting of dates and numbers etc. This helps to ensure that the XML is platform independent and interoperable. Take a look at using XmlConvert for xml data.

double value = XmlConvert.ToDouble(stringValue);