How to output a value on every third result of a foreach statement in php?

Question

I have a foreach statement in my app that echos a list of my database results:

Answer 1

<?php
$i = 0;
foreach($featured_projects as $fp) {
    echo '<div class="'.($i++%3 ? 'result' : 'other_class').'">';
    echo $fp['project_name'];
    echo '</div>';
}
?>

Answer 2

<?php
    $counter = 0;

    foreach ($featured_projects as $fp) {
        echo '<div class="result' . ($counter++ % 3 === 0 ? ' third' : '') . '">';
        echo $fp['project_name'];
        echo '</div>';
    }
?>

Answer 3

You can use a counter and the modulo/modulus operator as per below:

<?php

// control variable
$counter = 0;

foreach($featured_projects as $fp) {

    // reset the variable
    $class = '';

    // on every third result, set the variable value
    if(++$counter % 3 === 0) {
        $class = ' third';
    }

    // your code with the variable that holds the desirable CSS class name
    echo '<div class="result' . $class . '">';
    echo $fp['project_name'];
    echo '</div>';
}

?>

Answer 4

What leaves your code mostly in tact would be

<?php 
$i = 1;
foreach($featured_projects as $fp) {
printf ('<div class="%s">',(($i % 3) ? "result" : "result_every_third" ));
echo $fp['project_name'];
echo '</div>';
$i++;
}
?>

But you may want to consider using a for or while construct around "each($featured_projects)" (see http://php.net/manual/en/function.each.php) which may result in neater code.

Answer 5

If the $featured_projects array is based on incremental index you could simply use the index and the modulo % operator.

Otherwise you would have to add a counter.

http://php.net/manual/en/language.operators.arithmetic.php

Answer 6

<?php 
foreach($featured_projects as $fp) {
    if(++$i % 3 === 0) {
        $class = ' something';
    } else {
        $class = '';
    }
    echo '<div class="result' . $class . '">';
    echo $fp['project_name'];
    echo '</div>';
}
?>