I used following functions to convert DateTime
from/into string
:
DATE_OBJ.ToString(DATE_FORMAT);
DateTime.ParseExact(Date_string,
You cannot do this from DateTime
, as DateTime
holds no TimeZone
info.
This is close: string.Format("{0:s}", dt)
will give 2012-03-20T14:18:25
.
See: http://www.csharp-examples.net/string-format-datetime/
You could extend this to: string.Format("{0:s}.{0:fff}", dt)
, which will give 2012-03-20T14:18:25.000
But you better have a look at DateTimeOffset
: DateTime vs DateTimeOffset
(Not advisable, but to fake it and still use DateTime
: string.Format("{0:s}.{0:fff}+04:00", dt)
)
If that is a string you receive then you can split the string by T and use only the first part which is the Date component of the whole string and parse that.
ex:
string dateTimeAsString = "2012-03-20T14:18:25.000+04:00";
string dateComponent = dateTimeAsString.Splic('T')[0];
DateTime date = DateTime.ParseExact(dateComponent, "yyyy-MM-dd",null);
You can go from DateTime to that format with
DateTime dt = new DateTime();
dt.ToString("o");
and from that format to DateTime with
DateTimeOffset.Parse(dateString);
Here is some more info on DateTime format: http://www.dotnetperls.com/datetime-format
You are better of using DateTimeOffSet like:
string str = " 2012-03-20T14:18:25.000+04:00";
DateTimeOffset dto = DateTimeOffset.Parse(str);
//Get the date object from the string.
DateTime dtObject = dto.DateTime;
//Convert the DateTimeOffSet to string.
string newVal = dto.ToString("o");