I\'m trying to come up with a regular expression to validate a comma separated email list.
I would like to validate the complete list in the first place, then split
I agree with @crisbeto's comment but if you are sure that this is how you want to do it, you can do it by matching the following regex:
^(\s?[^\s,]+@[^\s,]+\.[^\s,]+\s?,)*(\s?[^\s,]+@[^\s,]+\.[^\s,]+)$
An easier way would be to remove spaces and split the string first:
var emails = emailList.replace(/\s/g,'').split(",");
This will create an array. You can then iterate over the array and check if the element is not empty and a valid emailadres.
var valid = true;
var regex = /^(([^<>()[\]\\.,;:\s@\"]+(\.[^<>()[\]\\.,;:\s@\"]+)*)|(\".+\"))@((\[[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}\])|(([a-zA-Z\-0-9]+\.)+[a-zA-Z]{2,}))$/;
for (var i = 0; i < emails.length; i++) {
if( emails[i] == "" || ! regex.test(emails[i])){
valid = false;
}
}
note: I got the the regex from here
const regExp = new RegExp(/^(\s?[^\s,]+@[^\s,]+\.[^\s,]+\s?,)*(\s?[^\s,]+@[^\s,]+\.[^\s,]+)$/);
const dom = document.getElementById("regExDom");
const result = regExp.test("test@gmail.com,test2@gmail.com,test3@test.com")
console.log("Regex test => ", result)
dom.innerHTML = result;
<div id="regExDom"></div>
I am using the Regex from many years and code is same. I believe this works for every one:
^(\w+((-\w+)|(\.\w+))*\@[A-Za-z0-9]+((\.|-)[A-Za-z0-9]+)*\.[A-Za-z0-9]{2,4}\s*?,?\s*?)+$
Be happy :)
Also note that you'll want to get rid of extra spaces so an extra step needs to be added as follows:
var emailStr = "felipe@google.com , felipe2@google.com, emanuel@google.com\n";
function validateEmailList(raw){
var emails = raw.split(',')
var valid = true;
var regex = /^(([^<>()[\]\\.,;:\s@\"]+(\.[^<>()[\]\\.,;:\s@\"]+)*)|(\".+\"))@((\[[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}\])|(([a-zA-Z\-0-9]+\.)+[a-zA-Z]{2,}))$/;
for (var i = 0; i < emails.length; i++) {
if( emails[i] === "" || !regex.test(emails[i].replace(/\s/g, ""))){
valid = false;
}
}
return valid;
}
console.log(validateEmailList(emailStr))
By adding .replace(/\s/g, "")
you make sure all spaces including new lines and tabs are removed. the outcome of the sample is true as we are getting rid of all spaces.