How to convert a PHP object to a string? [duplicate]

Answer 1

you can use php magic method __toString

Answer 2

I suspect that this is not a problem with the object not convertable to a string.

It's more like that you are assuming that a variable contains a string, (or something that can represented as a string), but it contains an object, and you are trying to echo that out.

Answer 3

Why do you need this string? If you just need to visualize it for debugging, you can use var_dump(), print_r(), or $s = print_r($var, 1); to really make it into a string for further theming. If you need to send the object as text to somewhere else (database, Javascript code), you have a choice of serialize, json_encode, XML conversion, and many more, depending on your exact situation.

Answer 4

You want to convert a PHP object to a string?

if neither var_dump, print_r, var_export, serialize, json_encode nor __toString is exactly what you're after maybe this can help you satisfy your needs.

For PHP 5.3 and above

<?php
$v = (object) array('a' => 1, 'b' => 2, 'c' => 3);
$r = new ReflectionObject($v);

echo $r->getName() .' {' . implode(', ', array_map(
     function($p) use ($v) {
         $p->setAccessible(true);
         return $p->getName() .': '. $p->getValue($v);
     }, $r->getProperties())) .'}';

Will output:

stdClass {a: 1, b: 2, c: 3}

For a more conventional approach compatible with previous PHP 5 flavours try

<?php
class ExampleClass {
    private $pvt = 'private';
    protected $prot = 'protected';
    public $pub = 'public';
}

$v = new ExampleClass();
$r = new ReflectionObject($v);

echo $r->getName() ." {\n";
foreach ($r->getProperties() as $p)
   if ($p->isPublic())
       echo "\tpublic ".$p->getName().': '.$p->getValue($v)."\n";
   else
       echo "\t".($p->isPrivate()?'private ':'protected ').$p->getName().",\n";
echo "}\n";

Which will print:

ExampleClass {
    protected pvt,
    protected prot,
    public pub: public
}

Answer 5

You do not try to convert this Object in string,it will not work. Just fetch exact value from that Object.

As a example if you got output as cost.this cost output is Object. so fetch exact value from this as follows

  $var=cost->Postage_cost;
  $var1=cost->other_cost;

Answer 6

from the error you get I assume you used the object as a parameter to a function that expects a string. the question is, why you did that and what you expect that function to with the object. and then before passing it to the function, extract a sensible string value.