Deferred execution in C#

Question

How could I implement my own deferred execution mechanism in C#?

So for instance I have:

string x = DoFoo();

Is it possible to perf

Answer 1

Why not just not call 'DoFoo()' until you want to?

-- Edit

I mean, what do you mean "use"

For example, if you want it to be called when '.ToString()' called, you can always inherit the class and implement your function there (but this would be quite unintuitive IMHO).

Answer 2

Instead of passing a string x, pass a delegate that procures you a string

Func<String> fooFunc=()=>DoFoo();

Answer 3

You pretty much describe LINQ in action. A linq query describes how to obtain the data, but data is retrieved (DoFunc is called) only when the query is iterated. Consider if you can change your design to accept IQueryable<string> where you need a string.

Answer 4

While it's somewhat dirty you could always use the yield keyword:

public IEnumerable<int> DoFoo() {
   Console.WriteLine("doing foo");
   yield return 10;
}

[Test]
public void TestMethod()
{
    var x = DoFoo();
    Console.WriteLine("foo aquired?");
    Console.WriteLine(x.First());
}

Answer 5

You can use lambdas/delegates:

Func<string> doit = () => DoFoo();
//  - or -
Func<string> doit = DoFoo;

Later you can invoke doit just like a method:

string x = doit();

---

I think the closest you can get is something like this:

Lazy<string> x = DoFoo;

string y = x; // "use" x

With a definition of Lazy<T> similar to this (untested):

public class Lazy<T>
{
    private readonly Func<T> func;
    private bool hasValue;
    private T value;

    public Lazy(Func<T> func)
    {
        this.func = func;
        this.hasValue = false;
    }

    public static implicit operator Lazy<T>(Func<T> func)
    {
        return new Lazy<T>(func);
    }

    public static implicit operator T(Lazy<T> lazy)
    {
        if (!lazy.hasValue)
        {
            lazy.value = lazy.func();
            lazy.hasValue = true;
        }
        return lazy.value;
    }
}

Unfortunately, it seems that the compiler's type inferencing algorithms can't auto-infer the type of the Func<T> and so can't match it to the implicit conversion operator. We need to explicitly declare the delegate's type, which makes the assignment statements more verbose:

// none of these will compile...
Lazy<string> x = DoFoo;
Lazy<string> y = () => DoFoo();
Lazy<string> z = delegate() { return DoFoo(); };

// these all work...
Lazy<string> a = (Func<string>)DoFoo;
Lazy<string> b = (Func<string>)(() => DoFoo());
Lazy<string> c = new Func<string>(DoFoo);
Lazy<string> d = new Func<string>(() => DoFoo());
Lazy<string> e = new Lazy<string>(DoFoo);
Lazy<string> f = new Lazy<string>(() => DoFoo);

Answer 6

One option is to use the Lazy<T> class, formerly from the parallel extensions library now a part of the .Net Framework 4.0.

• Reference: http://msdn.microsoft.com/en-us/library/dd642331(VS.100).aspx

It allows you to delay process data in a thread aware manner.