Type.GetType return null [duplicate]

Answer 1

If you know a type in the assembly that the target type lives in you can avoid hard coding the full assembly qualified name. For example:

Type.GetType(
    "MyAssembly.Foo.BarSubclass, " + typeof(MyAssembly.Foo.IBar).Assembly.FullName)

Answer 2

Try Type.GetType("caLibClient.entity.Web2ImageEntity, caLibClient"), according to Assembly qualified name

Answer 3

You need to add the assembly name as well, since your type isn't in the executing assembly (nor mscorlib.) So the call should be:

var myType = Type.GetType("caLibClient.entity.Web2ImageEntity, FullAssemblyName");

From the Type.GetType() docs:

typeName
Type: System.String
The assembly-qualified name of the type to get. See AssemblyQualifiedName. If the type is in the currently executing assembly or in Mscorlib.dll, it is sufficient to supply the type name qualified by its namespace.

From the docs for AssemblyQualifiedName, this is a sample name:

TopNamespace.SubNameSpace.ContainingClass+NestedClass, MyAssembly, Version=1.3.0.0, Culture=neutral, PublicKeyToken=b17a5c561934e089

Update: If you're already referencing the assembly in your project, and know at compile-time what the type-name is, you're better off saying

Type myType = typeof(caLibClient.entity.Web2ImageEntity);

since now you don't need to search for the type at run-time; the compiler will do everything for you.

Answer 4

You need to pass an assembly qualified name, in your case something like this:

var yourType = Type.GetType("caLibClient.entity.Web2ImageEntity,caLibClient");