Pass all arguments of a function to another function

Question

I want to have a class that I can create subclasses of that has a print function that only prints on a particular condition.

Here\'s basically what I\'m trying to do

Answer 1

class List(list):
    def append_twice(self, *args, **kwargs):
        self.append(*args, **kwargs)
        self.append(*args, **kwargs)

l = List()
l.append_twice("Hello")
print(l) # ['Hello', 'Hello']

Answer 2

Just duplicate the named arguments for the method signature.

def print(self, *args, end='\n', sep=' ', flush=False, file=None):
    if self.condition:
        print(*args, end=end, sep=sep, flush=flush, file=file)

Answer 3

Add at the end like this

def print(self, *args, end=''):

If the arguments are dynamic or too many:

 def print(self, *args, **kwargs):

Answer 4

I know it looks a bit ugly but works perfectly, if you are using a lot of keyword arguments and only want to build a facade for another method:

def print(self, print_message, end='\n', sep=' ', flush=False, file=None):
    if self.condition:
        print(**{key: value for key, value in locals().items() if key not in 'self'})

Although it's a lot of boilerplate, it avoids any duplication of parameter statements.

You might also look into using a decorator to make the conditional part more pythonic. But beware that the decorator checks the condition once prior to the class instantiation.

Answer 5

The standard way to pass on all arguments is as @JohnColeman suggested in a comment:

ClassWithPrintFunctionAndReallyBadName:
    ...
    def print(self, *args, **kwargs):
        if self.condition:
            print(*args, **kwargs)

args is a tuple of the non-keyword (positional) arguments, and kwargs is a dictionary of the keyword arguments.