Found in torvalds/linux-2.6.git -> kernel/mutex.c line 171
I have tried to find it on Google and such to no avail.
What does for (;;)
instruct?<
It is an infinite loop which has no initial condition, no increment condition and no end condition. So it will iterate forever equivalent to while(1).
It is functionally equivilent to while(true) { }
.
The reason why the for(;;)
syntax is sometimes preferred comes from an older age where for(;;)
actually compiled to a slightly faster machine code than while(TRUE) {}
. This is because for(;;) { foo(); }
will translate in the first pass of the compiler to:
lbl_while_condition:
mov $t1, 1
cmp $t1, 0
jnz _exit_while
lbl_block:
call _foo
jmp lbl_while_condition
whereas the for(;;)
would compile in the first pass to:
lbl_for_init:
; do nothing
lbl_for_condition:
; always
lbl_for_block:
call foo;
lbl_for_iterate:
; no iterate
jmp lbl_for_condition
i.e.
lbl_for_ever:
call foo
jmp lbl_for_ever
Hence saving 3 instructions on every pass of the loop.
In practice however, both statements have long since been not only functionally equivalent, but also actually equivalent, since optimisations in the compiler for all builds other than debug builds will ensure that the mov
, cmp
and jnz
are optimised away in the while(1)
case, resulting in optimal code for both for(;;)
and while(1)
.
It literally means "do nothing, until nothing happens and at each step, do nothing to prepare for the next". Basically, it's an infinite loop that you'll have to break somehow from within using a break
, return
or goto
statement.
It loops forever (until the code inside the loop calls break
or return
, of course. while(1)
is equivalent, I personally find it more logical to use that.
for(;;)
is an infinite loop just like while(1)
. Here no condition is given that will terminate the loop. If you are not breaking it using break
statement this loop will never come to an end.
It is same as writing infinite loop using " for " statement but u have to use break or some other statement that can get out of this loop.