\"I have a List of objects with a property \"CustomizationName\".
I want to join by a comma the values of that property, i.e.; something like this:
L
string foo = String.Join(",", myClasslist.Select(m => m.CustomizationName).ToArray());
If you want, you can turn this into an extension method:
public static class Extensions
{
public static string ToDelimitedString<T>(this IEnumerable<T> source, Func<T, string> func)
{
return ToDelimitedString(source,",",func);
}
public static string ToDelimitedString<T>(this IEnumerable<T> source, string delimiter, Func<T, string> func)
{
return String.Join(delimiter, source.Select(func).ToArray());
}
}
Usage:
public class MyClass
{
public string StringProp { get; set; }
}
.....
var list = new List<MyClass>();
list.Add(new MyClass { StringProp = "Foo" });
list.Add(new MyClass { StringProp = "Bar" });
list.Add(new MyClass { StringProp = "Baz" });
string joined = list.ToDelimitedString(m => m.StringProp);
Console.WriteLine(joined);