as title, how can I do that
from offical documentation just tell us that $delete can use argument \'object\' and \'key\'
but I want delete a component by its
You could use the beforeDestroy method on the component and make it remove itself from the DOM.
beforeDestroy () {
this.$root.$el.parentNode.removeChild(this.$root.$el)
},
No, you will not be able to delete a component directly. The parent component will have to use v-if
to remove the child component from the DOM.
Ref: https://vuejs.org/v2/api/#v-if
Quoted from docs:
Conditionally render the element based on the truthy-ness of the expression value. The element and its contained directives / components are destroyed and re-constructed during toggles.
If the child component is created as part of some data object on parent, you will have to send an event to parent via $emit
, modify (or remove) the data and the child component will go away on its own. There was another question on this recently: Delete a Vue child component
Instead of deleting your component from its parent you can still use v-if
on the first <div>
tag from the component itself. This would leave an empty component in your page and it's not best practice but may avoid handling events from parent.
I couldn't find instructions on completely removing a Vue instance, so here's what I wound up with:
module.exports = {
...
methods: {
close () {
// destroy the vue listeners, etc
this.$destroy();
// remove the element from the DOM
this.$el.parentNode.removeChild(this.$el);
}
}
};
Vue 3 is basically the same, but you'd use root
from the context argument:
export default {
setup(props, { root }){
const close = () => {
root.$destroy();
root.$el.parentNode.removeChild(root.$el);
};
return { close };
}
}
In both Vue 2 and Vue 3 you can use the instance you created:
const instance = new Vue({ ... });
...
instance.$destroy();
instance.$el.parentNode.removeChild(instance.$el);