How to select only matched sub-document of mongodb using python

Question

Document in Mongo ->

            {
             emp_id : 11
             proj_info : 
                    [{
                     proj_id : 91
                           


        

Answer 1

welcome to Stackoverflow, you can use ${project} method to reduce it to the scope of the subdocument and then you can use ${match} there, like this:

collectionObject.aggregate([
{'$match':"emp_id":'11'}},
{'$project': {"proj_info": 1}},
{'$match':"proj_id":'91'}},
{'$project': {"proj_team": 1}},
{'$match': {"member_emp_id":'55'}}])

Answer 2

Thanks but still I had to make some changes as it was not giving expected output, I made these changes =>

collectionObject.aggregate([
{'$match':{'emp_id': '11', "proj_info.pro_id": '11'   }},

{'$unwind': "$proj_info"},

{'$match': {"proj_info.proj_team.member_emp_id": '55' }},

{'$unwind': "$proj_info.proj_team"},

{'$project': {"proj_info.proj_team": 1,"_id" : 0}}

]):

and this worked for me.

Thanks for the help.