Python SWIG: convert C++ return parameter to return value, and convert raw C++ type to Python type

Question

I\'m trying to modify an existing SWIG Python interface for a C++ library, to add Python wrappers for more functions, and I would greatly appreciate some help from someone e

Answer 1

Just like $1 is a reference to the Python input object in the input typemap, $1 is a reference to the C++ output variable in the argout typemap. Using this, you can generate a Python object for that data and append it to the result.

Here's a functional example for Windows:

test.h

#ifdef EXPORT
#define API __declspec(dllexport)
#else
#define API __declspec(dllimport)
#endif

struct ResultType
{
    int x;
    double y;
};

API void execute(int x, double y, ResultType& result1, ResultType& result2);

test.cpp

#define EXPORT
#include "test.h"

API void execute(int x, double y, ResultType& result1, ResultType& result2)
{
    result1.x = 2 * x;
    result1.y = 2 * y;
    result2.x = 3 * x;
    result2.y = 3 * y;
}

test.i

%module test

%{
#include "test.h"
%}

%include <windows.i>

%typemap(in,numinputs=0) ResultType& %{
    // Create a persistent object to hold the result;
    $1 = new ResultType;
%}

%typemap(argout) ResultType& (PyObject* tmp) %{
    // Store the persistent object in a PyObject* that will be destroyed
    // when it goes out of scope.
    tmp = SWIG_NewPointerObj($1, $1_descriptor, SWIG_POINTER_OWN);
    $result = SWIG_Python_AppendOutput($result, tmp);
%}

%include "test.h"

Output

>>> import test
>>> r = test.execute(2,3)
>>> r[0].x
4
>>> r[0].y
6.0
>>> r[1].x
6
>>> r[1].y
9.0