I have a date object,
NSDate *date = [NSDate date];
Now I want a date earlier of this date and next of it. What function should I use.
Earlier and La
You need to use NSCalendar and NSDateComponents to do this calculation reliably.
Here's an example I have to hand to compute an NSDate for noon today. I'm sure you can work out how to get the result you want from this and the documentation.
NSDate *today = [NSDate date];
NSCalendar *gregorian = [[[NSCalendar alloc] initWithCalendarIdentifier:NSGregorianCalendar] autorelease];
NSUInteger unitFlags = NSYearCalendarUnit | NSMonthCalendarUnit | NSDayCalendarUnit;
NSDateComponents* todayComponents = [gregorian components:unitFlags fromDate:today];
todayComponents.hour = 12;
NSDate* noonToday = [gregorian dateFromComponents:todayComponents];
NSDate is a bit of a misnomer. It is a not a simple date, it is a date a time, with subsecond level precision. The earlierDate: method is a comparison function that returns which ever of the two dates is earlier, it does not create an earlier date. If all you care about is a date that is before your current one you can do:
NSDate *earlierDate = [date addTimeInterval:-1.0];
Which will return a date 1 second before date. Likewise you can do
NSDate *laterDate = [date addTimeInterval:1.0];
for a date 1 second in the future.
If you want a day earlier you can add a days worth of seconds. Of course that is approximate unless you deal with all the gregorian calendar issues, but if you just want a quick approximation:
NSDate *earlierDate = [date addTimeInterval:(-1.0*24*60*60)];
That doesn't work with leap seconds, etc, but for most uses it is probably fine.