Why is sizeof(array) different in these two cases? [duplicate]

Answer 1

Its because arrays that are function arguments get translated to pointers. so

void foo(int arr[8])

is actually

void foo(int *arr)

Answer 2

Arrays decay into pointers when passed into functions such that you are printing the sizeof the array pointer of int of 4 bytes in foo().

The sizeof(myarray) prints the size of the array which is 32 (num elements x size of int).